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Difficulty: 3/102024 IOQM 2024 (Q6)

Find the number of triples of real numbers (a, b, c) such that 20 + 20 + 20 = 24 + 24 + 24 = 1 .

Guide / Hint

Hint 1: Start by analyzing the initial conditions and setting up the basic equations. a20 + b20 + c20 = a24 + b24 + c24 = 1.

Hint 2: Look for algebraic properties, symmetry, or geometric theorems to simplify. If both equation have to satisfy.

Hint 3: Proceed with the final algebraic steps to solve the system. => Either or or = ±1.

Solution

Step 1: a20 + b20 + c20 = a24 + b24 + c24 = 1

Step 2: If both equation have to satisfy

Step 3: => Either or or = ±1

Step 4: And other have to be 0.

Step 5: So, if = 1

Step 6: => b=c=0

Step 7: If = –1

Step 8: => b=c=0

Step 9: Similarly, for and if = ±1

Step 10: => a=c=0

Step 11: And if = ±1

Step 12: => a=b=0

Step 13: Total triples = 6.

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