Find the number of triples of real numbers (a, b, c) such that 20 + 20 + 20 = 24 + 24 + 24 = 1 .
Hint 1: Start by analyzing the initial conditions and setting up the basic equations. a20 + b20 + c20 = a24 + b24 + c24 = 1.
Hint 2: Look for algebraic properties, symmetry, or geometric theorems to simplify. If both equation have to satisfy.
Hint 3: Proceed with the final algebraic steps to solve the system. => Either or or = ±1.
Step 1: a20 + b20 + c20 = a24 + b24 + c24 = 1
Step 2: If both equation have to satisfy
Step 3: => Either or or = ±1
Step 4: And other have to be 0.
Step 5: So, if = 1
Step 6: => b=c=0
Step 7: If = –1
Step 8: => b=c=0
Step 9: Similarly, for and if = ±1
Step 10: => a=c=0
Step 11: And if = ±1
Step 12: => a=b=0
Step 13: Total triples = 6.
Ready to track your progress and master these topics?
Create a free account